Linear Brakes for Dynamic Applications

Pneumatic Brakes
	MBPS - Pneumatic Braking Element
	BWPS - Pneumatic Braking Element
	TKPS - Pneumatic Braking Element
	UBPS - Pneumatic Braking Element
	RBPS - Pneumatic Round Shaft Braking Element
	LBPS - Pneumatic Braking Element

Hydralic Brakes
	KBH - Hydraulic Braking Element
	KBHS - Hydraulic Heavy Load Braking

Stopping with a Linear Brake?

Zimmer’s Linear BRAKES are used exclusively for DYNAMIC applications. Contact surfaces are made from a specially formulated brake material similar to automotive brake pads.

They are replaceable and have a recommended life of 2,000 cycles based on the application. Ideally suited to prevent un-intended gravity fall of machine motions, compliment an existing system or in the event of a complete power failure.

Advantages:

• Small envelope size with ultra high holding forces

• No relative movement

• End seals, adapter and distance plates

• Controllable and adjustable

• High rigidity

• Easy to install

• Custom models are available upon request

• Special friction-coating for brake line material is
proven for industrial applications

Event Chart

Events

A – Signal to stop given to control

B – Signal to stop given to brake

C – Brake fully applied

D – Device Stopped, V2 = 0 [m/s]

The response time of the corresponding valve should be determined from the respective manufacture, in particular when the valve is employed as a brake or a safety device against falling.

When employing the PLUS version we recommend pneumatic valves free of overflow or for example 5/3 way valves (with un-pressurized neutral position). When valves are used that are not free of overflow, overflow can occur at the piston seals when they are activated.

Force: [lbf] pound force, [N] Newtons

Note: .2248 [lbf] = 1 [N] or 1 [lbf] = 4.45 N

Displacement: [in.] inches, [m] metres

Note: 39.37 [in.] = 1 [m]

Pressure: [p.s.i.], MPa (mega-Pascals)

Note: 145.04 [p.s.i.] = 1 MPa

Calculations

Total Stopping Distance = SC + SR + SB

SC = V1·tC, tC = 0.04s (typical must confirm particular system performance)

SR = V1·tR, tR = 0.03s (typically)

SB can be found by equating the masses kinetic energy EK to the energy. The applied braking force multiplied by the braking distance, or EB.

EK = ½·m·V1² = EB = 2·FB·SB

Note: there are 2 brakes pads per Zimmer element.

SB = m·V1²

         4·µ·N

Where: m = Mass of moving machinery [kg]

              V1 = Velocity (initial) of moving machinery [m/s]

               µ = Coefficient of sliding friction

               N = Normal force applied by brake pad [N]

Factors that could affect the calculation

• Mounting altitude (vertical application)

• Lubrication

• Temperature

• Air pressure supply

• Misalignment

Calculation Assumptions

No change in initial velocity when brake is being applied or responding!